By Ron Larson

CALCULUS I WITH PRECALCULUS, brings you on top of things algebraically inside of precalculus and transition into calculus. The Larson Calculus software has been generally praised by means of a iteration of scholars and professors for its strong and powerful pedagogy that addresses the wishes of a huge diversity of training and studying types and environments. each one name is only one part in a accomplished calculus direction application that conscientiously integrates and coordinates print, media, and know-how items for winning instructing and studying. One fundamental goal guided the authors in penning this booklet: to boost distinctive, readable fabrics for college kids that sincerely outline and show suggestions and ideas of calculus.

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**Additional resources for Calculus I with Precalculus**

**Sample text**

9 7 8 9 Choose x = 9. −x + 8 < 0 x−5 ■ Copyright 2011 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s). Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.

3x Ϫ 1 Յ 5 20 < 6x Ϫ 1 3͑x ϩ 1͒ < x ϩ 7 2x ϩ 9 > 13 Խ Խ 1 2 Խx ϩ 1Խ Յ 3 In Exercises 83–88, find the interval(s) on the real number line for which the radicand is nonnegative. 83. Ίx Ϫ 5 85. Ίx ϩ 3 4 7 Ϫ 2x 87. Ί 84. Ίx Ϫ 10 86. Ί3 Ϫ x 4 6x ϩ 15 88. Ί Խ Խ 89. Think About It The graph of x Ϫ 5 < 3 can be described as all real numbers within three units of 5. Give a similar description of x Ϫ 10 < 8. 90. Think About It The graph of x Ϫ 2 > 5 can be described as all real numbers more than five units from 2.

250, is often called the Father of Algebra. He was the first to use abbreviated word forms in equations. x 3x ϩ ϭ2 3 4 x 3x ͑12͒ ϩ ͑12͒ ϭ ͑12͒2 3 4 4x ϩ 9x ϭ 24 24 xϭ 13 Write original equation. Multiply each term by the LCD of 12. Divide out and multiply. Combine like terms and divide each side by 13. Check x 3x ϩ 3 4 24͞13 3͑24͞13͒ ϩ 3 4 8 18 ϩ 13 13 26 13 So, the solution is x ϭ ϭ2 Write original equation. ϭ2 Substitute 24 13 for x. ϭ2 Simplify. ϭ2 Solution checks. ✓ 24 13 . ■ Multiplying or dividing an equation by a variable quantity may introduce an extraneous solution.